Consider There are 2 isomers even for 2f-dck which include S and R the R isomer is a 3rd as potent since the S isomer among the other issues. What you have got is really a racemic 50/50 combination of each and every isomer. So you have to multiply your https://mixbookmark.com/story14312314/not-known-factual-statements-about-buy-2-fdck